F(1)=4x^2+2x+7

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Solution for F(1)=4x^2+2x+7 equation: 



(1)=4F^2+2F+7

We move all terms to the left:

(1)-(4F^2+2F+7)=0

We get rid of parentheses

-4F^2-2F-7+1=0

We add all the numbers together, and all the variables

-4F^2-2F-6=0

a = -4; b = -2; c = -6;
Δ = b2-4ac
Δ = -22-4·(-4)·(-6)
Δ = -92
Delta is less than zero, so there is no solution for the equation

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